Question

3¹⁰+3⁹-3⁸×2⁴+3⁸×2⁴ solve​

Answer 1

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Answer 2

Given:

The given expression is: $3^{10}+3^9-3^8\times2^4+3^8\times2^4$.

To find:

We need to solve the given expression.

Solution:

Consider the given expression,

$\Rightarrow 3^{10}+3^9-3^8\times2^4+3^8\times2^4$

Before solving it, we need to find their individual values first.

• The value of $3^{10}$ is equal to 59049.
• The value of $3^{9}$ is equal to 19683.
• The value of $3^{8}$ is equal to 6561.
• The value of $2^4$ is equal to 16.
• The value of $3^{8}$ is equal to 6561.
• The value of $2^4$ is equal to 16.

Now substitute the above values in given expression,

$\Rightarrow 3^{10}+3^9-3^8\times2^4+3^8\times2^4$

$\Rightarrow 59049+19683-6561\times16+6561\times16$

Simplifying the terms,

$\Rightarrow 59049+19683-104976+104976$

Rearranging the terms,

$\Rightarrow 59049+19683+104976-104976$

Adding the terms,

$\Rightarrow 59049+19683$

$\Rightarrow 78732$

Therefore, the value of given expression is 78732.