Question

31 3rd term of an arithmetic sequence is 40 and 41 th term is 50 then find the common difference also find the 61th term

Answer 1

Answer:

common difference is 10/38 and 6th term is 70/38

Step-by-step explanation:

given:

a3=40

a+2d=40-------(i)

also,a+40d=50-----(ii)

(ii)- (i)

38d=10

a=20/38

common difference = 10/38

6 th term=a+5d=20/38+5*10/38=70/38