Question

31.A bus starting from rest-moves with uniform acceleration of 0.1 ms22 for 2 minutes, find :

(a) the speed acquired.

(b) the distance travelled.

Answer 1

Hello,

The constant acceleration =0.1 m/sec^2

Time =2 minutes =120 seconds

Now,
The bus started from rest
So, the initial velocity will be 0m/sec

So now

Final velocity =?

We know that
V=u +at
So, since u =0 m/sec
So,
V= at
V = 0.1 *120 = 12 m/sec

Now, the final velocity is 12 m/sec
So,
We again know that
2as = v²-u²
Since, u =0m/sec
So,
2as = v²
s = v²/2a
The distance travelled is
$s = \frac{ {v}^{2} }{2a} \\ \\ s = \frac{144}{2 \times 0.1} = \frac{144}{0.2} \\ \\ s = \frac{144 \times 10}{2} = 72 \times 10 = 720m$
So,

The distance covered is equal to 720 metres.

Hope this will be helping you ✌️