Question

31.
A lift is moving upwwards with a constant speed of 5 m/s. The speed of one of the pulleys 5 m
s as shown. Then the speed of second puley is :
5 m/s
a) 5 m/s
b) zero
e) 7.5 m/s
d) 10 m/s
​

Answer 1

Speed of second pully is 5 m/s

Explanation:

Given,

u = 5 m/s

Speed of second pulley, $V_s$ = ?

According to the question,

$\frac{u}{2} = 5$ m/s

$u = 10$ m/s

$\frac{10 + 0}{2} = V_s$

or,

$V_s = 5$ m/s