Question

31. A rectangular plot is given for constructing a house, having a
measurement of 40 m long and 15 m in the front. According to the laws,
a minimum of 3-m-wide space should be left in the front and back each
and 2 m wide space on each of the other sides. Find the largest area
where house can be constructed.​

Answer 1

Answer:

324 $m^{2}$

Step-by-step explanation:

length = 40 m

breadth = 15 m

according to the law

new length (l 2) = 40-(2+2) m = 40-4 m =36 m

mew breadth (b 2) = 15-(3+3) m = 15-6 m = 9 m

∴ area in which house can be constructed = l 2 × b 2

                                                                       = 36 m × 9 m

                                                                       = 324 $m^{2}$

Answer 2

Answer:

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