Physics, asked by drposani, 1 day ago

31 An uncharged capacitor is charged by a batery and work done by battery is 2 E. This capacitor is then disconnected from the battery and combined with an identical uncharged capacitor. The total energy loss when steady state is reached
a) 3E/4. b)E/2. c)3E/2. d)3E/8​

Answers

Answered by 8apavneetbissingh
1

Answer:

Correct option is c

Explanation:

Q

1

+Q

2

=Q

0

By KVL,

C

Q

1

C

Q

2

=0

or, Q

1

=Q

2

Q

1

+Q

2

=Q

0

Q

1

=Q

2

=Q

0/2

E

final

=

2c

1

(

2

Q

)

2

+

2c

1

(

2

Q

)

2

=

2c

1

4

Q

2

+

2c

1

4

Q

2

4c

Q

E

Q

E

f

=

2

1

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