Question

31 by 2 is equal to 2 by 3 solve the following question

Answer 1

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1.ANSWER

Given, P(A)=31,P(B)=72,P(C)=83

Probability that the question is solved only by one student is

=P(A)×P(B)c×P(C)c+P(A)c×P(B)×P(C)c+P(A)c×P(B)c×P(C)

=(31×75×85)+(32×72×85)+(32×75×83)=5625

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