Question

31. Figure shows a projectile thrown with speed
u = 20 m/s at an angle 30° with horizontal from
the top of a building 40 m high. Then the
horizontal range of projectile is
40 m​

Answer 1

Answer:

1385.6

Explanation:

horizontal range = u2 sin 2 theta÷g

R= 20 sin 30÷ 10 ×40

=400 × 1.732÷2 ÷ 10 × 40

=400 × 0.866 ÷ 10 × 40

=34.64×40

=1385.6