Question

31.
If K.E. of a particle is doubled then its
momentum will :
(A) remain unchanged
(B) be doubled
(C) be quadrupled
(D) increase V2 times
​

Answer 1

KE = 1/2 mv²

$= \frac{1}{2} m {v}^{2} \times \frac{m}{m} \\ \\ \frac{1}{2} \frac{ {m}^{2} {v}^{2} }{m} \\ \\ = \frac{1}{2} \frac{p}{m} \\ where \: p \: is \: momentum$

$</p><p>K E\: \alpha \frac{p}{2}$

2 KE α 2×p/2

so momentum will be unchanged