Question

31. If log (a/b) + log (b/a) = log(a + b), then​

Answer 1

Answer:

loga/b+logb/a=log(a+b)

But logx/y=logx-logy

So,

loga-logb+logb-loga=log(a+b)

0=log(a+b)

but log1=0

log1=loga+b

a+b=1