31. In the given figure, triangle ABC is an isosceles triangle with AB = AC.
The bisectors of the exterior angles meet at O. If angle BOC = 70°,
then the measure of angle A is:
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Answer:
angle A measures 95°
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B=C as opposite angles of similar sides are equal
therefore angle OBC=angle OCB
so by angle sum property of triangle BOC
BOC+OBC+OCB=180
70+OBC+OBC=180
2OBC=110
OBC=55
AE is a line
CBE+B=180
2OBC+B=180
110+ B=180
ABC=70
A+B+C=180
A+70+70=180
A+140=180
A=40
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