Question

31. In this figure D is a midpoint of AB, P is a point on AC such that PC = 1

2

AP and DE || BP

show that AP – EP = PC​

Answer 1

Answer:

AP-EP=PC

Step-by-step explanation:

Let first consider the triangle ABP

now here, DE is the lies on the middle of AB and is parallel to BP

now as DE lies on 1/2 of AB and is parallel to BP .EP therefore also lies of 1/2 of AP

Now we can say EP =1/2 of AP= PC and

therefore, AP- EP=PC verified