31. Prove that: sin (1 + tan 0) + cos 0 (1 + cot0) = sec 0 + cosec 0.
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Answer:
sin (1+tan)+cos (1+cot)=sec+cosec
=> LHS= sin (1+tan)+cos (1+1/tan)
=> sin (1+tan)+cos (1+tan)/tan
=> (1+tan)(sin+cos/tan)
=> (1+tan)(sin.tan+cos)/tan
=> (1+tan)(sin^2/cos+cos)/tan
=> (1+tan)(sin^2+cos^2)/tan.cos
=>(1+tan)/tan.cos
=>(1/tan.cos)+tan/tan.cos
=>( cot/cos)+(1/cos)
=> cosec +sec
LHS= RHS.
Step-by-step explanation:
Answered by
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The above is your solution. Please ignore the cut out part
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