Math, asked by nihaltaye11, 3 months ago

31. Prove that: sin (1 + tan 0) + cos 0 (1 + cot0) = sec 0 + cosec 0.​

Answers

Answered by neeturai228
1

Answer:

sin (1+tan)+cos (1+cot)=sec+cosec

=> LHS= sin (1+tan)+cos (1+1/tan)

=> sin (1+tan)+cos (1+tan)/tan

=> (1+tan)(sin+cos/tan)

=> (1+tan)(sin.tan+cos)/tan

=> (1+tan)(sin^2/cos+cos)/tan

=> (1+tan)(sin^2+cos^2)/tan.cos

=>(1+tan)/tan.cos

=>(1/tan.cos)+tan/tan.cos

=>( cot/cos)+(1/cos)

=> cosec +sec

LHS= RHS.

Step-by-step explanation:

Answered by ravigargrud
1

The above is your solution. Please ignore the cut out part

Attachments:
Similar questions