Question

 31 st term of arithmetic Sequence 8,11,14____is *​

Answer 1

Answer:

98

Step-by-step explanation:

AP:  8,11,14...

a = 8, d = 11-8 = 3

$a_{31}$ = a + 30d

$a_{31}$ = 8 + 30(3)

     = 8 + 90

      = 98

therefore the 31st term of the following arithmetic Sequence is 98

Answer 2

Answer:

98

Step-by-step explanation:

nth term of a.p is a+(n-1)d

here n is 31 then it is a + 30d

where a=8 d=3

d= A2-A1

A+30D

8+30(3)=98