31. The angle of the elevation of the top of the pole from a point xm away from th
pole is 60. then the height of the pole is
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0
Answer:
Let the height of pole be PQ=h m.
And QB=d be the distance between B and foot of pole.
tan60
0
=
d
h
⇒d=
3
h
tan30
0
=
100−d
h
⇒−
3
h
+100=
3
h
⇒100=h(
3
+
3
1
)
⇒h=25
3
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