Question

31. The circular scale of a screw gauge has 50 divisions and the pitch is 0.5 mm. Find the
diameter of sphere. Main scale reading is 2.

C) 2.20 mm
B) 1.25 mm
A) 1.2 mm

D) 2.25 ​

Answer 1

Answer:

Your answer is 2.25 mm

Explanation:

Pitch of a circular scale P = 0.5 mm

No of division on circular scale = 50

So least count of screw gause LC = P upon N

= 0.5 upon 50 mm which will be 0.01

Now main scale reading is given as M.S.R +n *LC

D = 2 mm + 25 *0.01 mm = 2.25 mm

So your answer will be option D

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