Question

31. The inner diameter of a glass is 7 cm and it
has a raised portion in the bottom in the
shape of a hemisphere, as shown in the
figure. If the height of the glass is 16 cm,
find the apparent capacity and the actual
capacity of the glass.
​

Answer 1

We have,

The height of the glass, h = 16 cm and

The base radius of the cylinder = the base radius of the hemisphere, r = 7/2 cm

Now,

The apparent capacity of the glass = Volume of the cylinder

= πr2h

= 227×72×72×16

We have,

The height of the glass, h = 16 cm and

The base radius of the cylinder = the base radius of the hemisphere, r = 7/2 cm

Now,

The apparent capacity of the glass = Volume of the cylinder

= πr2h

= \(\frac {22} {7} \times \frac {7} {2} \times \frac {7} {2} \times 16 \]”>

= 616 cm3

Also,

The actual capacity of the glass = Volume of cylinder – Volume of hemisphere

= 616–23πr3

= 616–23×227×72×72×72

= 616–5396

= 31576

= 526. 17 cm3

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Answer 2

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