Question

31. The numerator of a fraction is 6 less than denominator. If 3 is added to the
numerator and 1 is subtracted from the denominator, the fraction is equal to
2/3. Find the original fraction.
S1
पाटनले​

Answer 1

Answer:

1/7

Step-by-step explanation:

Let the denominator be x.

numerator = x-6

BTP

$\frac{x-6+3}{x-1} = \frac{2}{3}$

$\frac{x-3}{x-1} = \frac{2}{3}$

$3(x-3)=2(x-1)$

$3x-9 = 2x-2$

$x= 7$

∴ original fraction = 1/7

Answer 2

Step-by-step explanation:

Answer:

1/7

Step-by-step explanation:

Let the denominator be x.

numerator = x-6

BTP

\frac{x-6+3}{x-1} = \frac{2}{3}

x−1

x−6+3

=

3

2

\frac{x-3}{x-1} = \frac{2}{3}

x−1

x−3

=

3

2

3(x-3)=2(x-1)3(x−3)=2(x−1)

3x-9 = 2x-23x−9=2x−2

x= 7x=7

∴ original fraction = 1/7