Question

31. The radil of two concentric circles are 41 cm and 40 cm. A chord of the circle with
bigger radius touches the circle with smaller radius. Find the length of that chord.
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Answer 1

Given

The radil of two concentric circles are 41 cm and 40 cm. A chord of the circle with  bigger radius touches the circle with smaller radius. Find the length of that chord.

Answer

OC=40cm,OB=41cm

OC⊥AB since AB is tangent to the smaller circle .

⟹AC+BC

In △OCB

$OB^{2}$=$OC^{2}$+$BC^{2}$

⟹$BC^{2}$=$41^{2}$-$40^{2}$=818×1

⟹BC=9cm

⟹AB=2BC=18cm

Hence the answer is 18cm

#Angry prash

#ANGRY ARMY

Answer 2

here is your correct answer