Physics, asked by ramcharanyadav3531, 10 months ago

31. The sink temperature of a heat engine 77°C.
The efficiency is 30%. The source temperature
is
a) 500°C
b)227°C
c)317°C
d)427°C​

Answers

Answered by vishu592
0

Answer:

Taking the sink temperature (T2) =77°c=351k efficiency (eta) be 30%=.30 source temperature (T1) =? Efficiency =(T1-T2) /T1 efficiency =1-T2/T1 T2/T1=1- efficiency T1=T2/(1-efficency) T1=351/(1-.30) T1=361k=88°c

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