Question

31. The solution of x dy - ydx + x²e² dx = 0 is :
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Answer 1

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=> y/x + e^x = c

Given equations is

x dy - ydx + x²e² dx = 0

=> x dy - ydx + x²e² dx = 0

=> (x dy - ydx)/x² + e² dx = 0

=> d(y/x) + d(e^x) = 0

On integrating both sides, we get

y/x + e^x = c

silentlover45.❤️

Answer 2

Answer

=> y/x + e^x = c

Given equations is

x dy - ydx + x²e² dx = 0

=> x dy - ydx + x²e² dx = 0

=> (x dy - ydx)/x² + e² dx = 0

=> d(y/x) + d(e^x) = 0

On integrating both sides, we get

y/x + e^x = c