Question

31. The tension T in the string shown in figure is
10 kg
u=0.7
130.
(1) Zero
(3) 35√3 N
(2) 50 N
(4) (√3 – 1) 50 N​

Answer 1

Answer:

weight of block along plane , W = mgsin30°

= 10kg × 10 m/s² × 1/2

= 50N

weight of block perpendicular to plane = normal reaction between block and wedge = mgcos30°

= 10kg × 10m/s² × √3/2

= 50√3 N

as block has tendency to move downward so, frictional force acting just opposite direction of it.

friction force, fr = μN =0.7 × 50√3 N

= 35√3 N = 60.62 N( approx)

here you can see , frictional force > weight of body along plane

so, body can't move downward, it will be rest and doesn't experience any force.so, tension in string must be zero.