Question

31. The unit of van der Waals constant a is 1) Кра 2) KPa dm3 3) KPa dm mol-1 4) KPa dm mol-2 32. At low pressures, the van der Wall's equation is written as P + 2 v=RT V The compressibiltiy factor is then equal to: 1) 2) 1 a RTV a 3)(-+ RTV) 4) (1+RT 1+ RTV a a 22 0​

Answer 1

are u asking electron configuration??

then it's your answer.

2,8,18,32,50,18