Question

31. When the length of a simple pendulum is
increased by 22 cm, the period changes by
20 %. Find the original period of simple
pendulum. Ig - 9.8 m/s)
Ans: 0.5 m​

Answer 1

Let the time period be T with length of pendulum be lcm.As per the question increasing l by 22cm brings the period change by 20%=>the eqn for time period be 1.2T=2π√{(0.01l+0.22)/9.8},again as T=2π√(0.01l/9.8).