Question

312x+138y=202; 138x+312y=173

Answer 1

Given,

First equation = 312x+138y = 202

Second equation = 138x+312y = 173

To find,

The values of x and y

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Here, we can simply use the normal algebraic method.

312x+138y = 202

23×(312x+138y) = 23×202

7176x+3174y = 4646....(1)

And,

138x+312y = 173

52×(138x+312y) = 52×173

7176x+16224y = 8996...(2)

Subtracting (2) from (1), we get that,

7176x+16224y-7176x-3174y = 8996-4646

13050y = 4350

y = 4350/13050

y = ⅓

Now,

312x + (138 × ⅓) = 202

312x + 46 = 202

312x = 156

x = ½

Hence, value of x is ½ and value of y is ⅓