Question

313(ABP +BC2 + AC?)=4(ADP + BE? + CF2)
4) None
The diameter of a circle is AB and the chord CD is equal to the radius. Lines AC
and BD intersect each other at point P, then find the value of P.
P
a​

Answer 1

Answer:

10.42,AB is a diameter of the circle,CD is a chord equal to the radius of the circle.AC and BD when extended intersect at point at E. Prove that ∠AEB = 60 degree . In Fig. 10.42,AB is a diameter of the circle,CD is a chord equal to the radius of the circle.AC and BD when extended intersect at point at E.

Step-by-step explanation:

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