Question

32-2(x-4)^2 factorize completely

Answer 1

Answer :

Now,

32 - 2 (x - 4)^2

= 2 {16 - (x - 4)^2}

= 2 {4^2 - (x - 4)^2}

= 2 {4 - (x - 4)} {4 + (x - 4)},
using the identity (a + b)(a - b) = a^2 - b^2

= 2 (4 - x + 4) (4 + x - 4)

= 2 (8 - x) (x)

= 2 x (8 - x),

which is the required factorization.

#MarkAsBrainliest

Answer 2

Hi there!

32 - 2(x - 4)²

= 2 [ 16 - (x - 4)² ]

= 2 [ 4² - (x - 4)² ]

= 2 [ 4 - (x - 4) ] [4 + (x - 4) ] ---{ Identity :- a² - b² = (a + b)(a - b) }

= 2 (4 - x + 4) (4 + x - 4)

= 2 (8 - x) (x)

= 2x (8 - x)

Hence,
The required factorisation is :- 2x (x - 8)

Hope it helps! :)