Question

32 - 34x + 2x² factorize​

Answer 1

32 - 32x - 2x + 2x²

32 ( 1 - x) - 2x ( 1 - x)

( 1 - x ) × ( 32 - 2x )

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Answer 2

Answer:

The factors of $2x^{2} -34x+32$ are $(x-1)\ ,\ (x-16)\ , \ 2$.

Step-by-step explanation:

$2x^{2} -34x+32$  is a  quadratic polynomial with $a=2,\ b=-34,\ c=32$ ,

where the general form of the quadratic equation is $ax^{2} +bx+c$ .

The factorization can be done by equating the polynomial to zero.

That is, $2x^{2} -34x+32=0$ .

To find the values of $x$ , there are three methods.

1. By using quadratic formula
2. By the method of factorization
3. By completing the square method.

We can solve this polynomial by the method of factorization.

Under this method , we have to find two numbers such that their sum is the coefficient of $x$ in the equation, and their product is the constant term in the equation.

So ,consider the equation $2x^{2} -34x+32=0$ (dividing throughout by two,)

$x^{2} -17x+16=0$

Now by inspection we can see that the numbers $-1,\ -16$ , will give their sum as $-17$ and product as $16$ .

Therefore the factors of the quadratic equation are

$(x-1),\ (x-16)\ , \ 2$ .

Hence the answer.

thank you