Question

32,40,56. find the hcf

Answer 1

Here is your answer

32= 2x2x2x2x2
40= 2x2x2x5
56= 2x2x2x7

HCF = 2x2x2. =8

Hope it helps you

Answer 2

Answer:

The HCF of 32, 40, and 56 will be 8.

Step-by-step explanation:

Given: The numbers are 32, 40, and 56.

We have to find the HCF of the above numbers.

• For this, we will first find the factors of the above numbers.
• And then, the largest positive integer that divides each of the given integers will be the HCF of the above numbers.

We are solving in the following way:

We have,

The numbers are 32, 40, and 56​​.

The factors of the above numbers will be:

The factors of 32 are: $1, 2, 4, 8, 16, 32$

The factors of 40 are: $1, 2, 4, 5, 8, 10, 20, 40$

The factors of 56 are: $1, 2, 4, 7, 8, 14, 28, 56$

From the above, we can see that 8 is the largest positive integer that divides each of the above integers

So, the greatest common factor(HCF) is 8.

NOTE:

Q. Find the HCF of 32,40,56.