Question

√32+√48-√192 ka maan nikala​

Answer 1

Answer:

=√32+√48-√192

=√(2×2×2×2×2)+√(3×2×2×2×2)+

√(3×2×2×2×2×2×2)

=√(2²×2²×2)+√(3×2²×2²)

+√(3×2²×2²×2²)

=(2×2×√2)+(2×2√3)+(2×2×2√3)

=4√2+4√3+8√3

=4(√2+√3+2√3)

=4(√2+3√3)

Correct me if I'm wrong.