Math, asked by pagalmath1732, 7 months ago

√32+√48÷2√8+2√12
What is the answer of this

Answers

Answered by kovid42010
0

Answer:

I think we have S2 = Z0/2 + Z4/(2 √ 3) and S5 = Z2/4 + ... + Z8/(8 2) + Z9/(8 2) + Z18/(32 3) + Z19/(32 3) +Z20/(32 √ 3) √ 6 0 S12 = Z0/4 + 3 ... + 3Z5/(10 √ 2) + 3Z12/(32 √ 5) +Z13/(6 √ 10) + √ 5Z14/(48 √ 2) + 3Z24/(160

Step-by-step explanation:

Similar questions