Math, asked by saravanan9, 1 year ago

(√32-√5)^1\3×(√32+√5)^1\3

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Answers

Answered by Sharonibose
37

Answer

3 is the answer

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Answered by mysticd
53

 \red { ( \sqrt{32} - \sqrt{5} )^{\frac{1}{3}} \times ( \sqrt{32} + \sqrt{5} )^{\frac{1}{3}} }

=  \Big(( \sqrt{32} - \sqrt{5} )( \sqrt{32} + \sqrt{5} )\Big)^{\frac{1}{3}}

 \blue { We\:are \:using \: following \: formulae :}

  \pink {i)a^{m} \times b^{m} = (ab)^{m} }

 \pink {ii) (a^{m})^{n} = a^{m \times n }}\\\pink { iii) (a + b )(a - b) = a^{2} - b^{2} }

 = [ (\sqrt{32})^{2} - (\sqrt{5})^{2})^{\frac{1}{3}}

 = ( 32 - 5 )^{\frac{1}{3}} \\= 27^{\frac{1}{3}}\\= (3^{3})^{\frac{1}{3}} \\= (3)^{3 \times \frac{1}{3}} \\= 3

Therefore.,

 \red { ( \sqrt{32} - \sqrt{5} )^{\frac{1}{3}} \times ( \sqrt{32} + \sqrt{5} )^{\frac{1}{3}} }\green {= 3}

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