Question

√32+√50+√72/√18+√98 simplify

Answer 1

$\sqrt{32} + \sqrt{50} + \frac{ \sqrt{72} }{ \sqrt{18} } + \sqrt{98}$

lets simplify the term under roots
32= 4×4×2
$\sqrt{32} = 4\sqrt{2}$
50= 5×5×2
$\sqrt{50} = 5\sqrt{2}$
72= 6×6×2
$\sqrt{72} = 6\sqrt{2}$
18 = 3×3×2
$\sqrt{18} = 3\sqrt{2}$
98= 7×7×2
$\sqrt{98} = 7\sqrt{2}$

$= 4 \sqrt{2} + 5 \sqrt{2} + \frac{6 \sqrt{2} }{ 3\sqrt{2} } + 7 \sqrt{2}$

$=16 \sqrt{2} + 2$

Answer 2

\sqrt{32} + \sqrt{50} + \sqrt{72} \div \sqrt{18} + \sqrt{98} \\ 4 \sqrt{2} + 5 \sqrt{2} + 6 \sqrt{2} \div 3 \sqrt{2} + 7 \sqrt{2}

$\sqrt{32} + \sqrt{50} + \sqrt{72} \div \sqrt{18} + \sqrt{98} \\ 4 \sqrt{2} + 5 \sqrt{2} + 6 \sqrt{2} \div 3 \sqrt{2} + 7 \sqrt{2} \\ 16 \sqrt{2} + 2$