32. 60 gr of gaseous C2H6 are mixed with 28 g of gaseous CO. The pressure of the resulting gaseous mixture
is 3 atm the partial pressure of C2H6. The mixture is__________
atm.
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Explanation:
Given P=1atm
V=28l
T=8273
128g of O
2
produce CO
2
mixture of C
2
H
6
& C
2
H
4
PV=nRT
1×28=n×0.082×8273
total moles =0.04127
C
2
H
6
+C
2
H
4
=0.04127
a+b=0.04127...(1)
C
2
H
6
+
2
7
O
2
→2CO
2
+3H
2
O
C
2
H
4
+3O
2
→2C
2
+2H
2
O
2
7a
+3b=
32
128
...(2)
find value of a & b from eq
n
(1) & (2)
mole fraction of C
2
H
6
=
totalmoles
a
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