Question

32.65 g of a Zn metal reacts with 350 mL of 1.5 M HCI . Calculate the weight of ZnCl , formed . ( Take molar mass of Zn = 65.3 and CI = 35.5 g / mol )​

Answer 1

Answer: 25.2g approx

Explanation:

moles of Zn= 32.65g/65.3= 0.5

moles of HCL=1.5M × 0.35L = 0.5

Zn + 2HCl → ZnCl2 + H2

here HCl is limiting reagent because 0.5 of HCl will react with 0.5/2 i.e. 0.25moles of Zn.

So only 0.25 moles of ZnCl2 will be formed i.e. 0.25× (65.3 + 35.5) = 0.25× 100.8 =

25.2g of ZnCl2 will be formed✌️

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