Question

32=7,54=23,76=47,98=79,109=?

Answer 1

#3*2+1=7
4*3+2=14
#5*4+3=23
6*5+4=34
#7*6+5=47
8*7+6=62
#9*8+7=79
#10*9+8=109

Ash marked equations are the answers for the question u asked.

Answer 2

The value of given series 32 = 7, 54 = 23, 76 = 47, 98 = 79, 109 = ? is 98.

Solution:

Given: 32 = 7, 54 = 23, 76 = 47, 98 = 79, 109 = ?

Let us first find out the relation between 7 and 32 and 23 and 54.

32 = 7, if we multiply the two digits 3 and 2, we get 6 and if we add 1 (second  digit i.e.2 minus 1) then we get 7 as an answer. In other words,

Multiply the two digits + second digit -1 = Answer

$3 \times 2+(2-1)=6+1=7$

54 = 23. If we multiply the two digits 5 and 4, we get 20 and if we add 3  (second digit 4 minus 1) then we get 23 as an answer. In other words,

$5 \times 4+(4-1)=20+3=23$

76 = 47  

$7 \times 6+(6-1)=42+5=47$

98 = 79

$9 \times 8+(8-1)=72+7=79$

109 = 98

$\bold{10 \times 9+(9-1)=90+8=98}$

Hence, the final answer 109 = 98.