32. A 60 kg man skating with a speed of 10 m/s collides
with a 40 kg skater at rest and they cling to each other.
Find the loss of kinetic energy during the collision.
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let 60 kg man has mass m1
let his velocity be v1
let 40 kg man has mass m2
Initial kinetic energy = m1v^2/2
=(60×10×10)/2=3000J
According to conservation of momentum,
m1v1 +m2v2 =( m1+m2)V
60×10 + 40×0 =(60+40)V
V=6m/s
Final kinetic energy ={(m1+m2)v^2}/2=(100*6*6)/2= 1800J.
Therefore loss in kinetic energy = 3000-1800=1200J
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