32*a*a*x*x*x- 8*b*b*x*x*x
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Answered by
1
Hey there !!!!!!!
=32*a*a*x*x*x-8*b*b*x*x*x
We know that 32 = 2*2*2*2*2 =2⁵ 8 =2*2*2 =2³
So, 2⁵*a²*x³-2³*b²*x³
=x³*2³(2²a²-b²)
Now ((2a)²-b²) =(2a+b)(2a-b)
=x³*2³(2a+b)(2a-b)
Hope this helped you................
=32*a*a*x*x*x-8*b*b*x*x*x
We know that 32 = 2*2*2*2*2 =2⁵ 8 =2*2*2 =2³
So, 2⁵*a²*x³-2³*b²*x³
=x³*2³(2²a²-b²)
Now ((2a)²-b²) =(2a+b)(2a-b)
=x³*2³(2a+b)(2a-b)
Hope this helped you................
amanbhandaricool:
but how???
Answered by
0
32×a×a×x×x×x – 8×b×b×x×x×x
= 32a²x³ – 8b²x³
= 8x³(4a²-b²)
=(2x)³[(2a)²-b²)]
= (2x)³(2a-b)(2a+b)
=2³.x³(2a-b)(2a+b)
Hope it helps
= 32a²x³ – 8b²x³
= 8x³(4a²-b²)
=(2x)³[(2a)²-b²)]
= (2x)³(2a-b)(2a+b)
=2³.x³(2a-b)(2a+b)
Hope it helps
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