Question

32. A, B, C and D share a certain amount amongst
themsclves. B sees that the other three get 3 times
what he himself gets C sees that the other three
get 4 times what he gets, while D sees that the
other three get 5 times what he gets, if the sum of
the largest and smallest shares is 99, what is the sum
of the other two shares?
(a) 99
(6) 81
(c) 64
(d) 54​

Answer 1

Answer:

Step-by-step explanation:

64 is the answer.

Answer 2

Answer:

Option (b) 81 is correct answer.

Step-by-step explanation:

(i) A + C + D = 3B.

(ii) A + B + D = 4C

(iii) A + B + C = 5D.

(iv) A + D = 99.

Substitute (iv) in (ii), we get

B + 99 = 4C

(B + 99)/4 = C    ------ (v)

Substitute (v) in (1), we get

⇒ 99 + (B + 99)/4 = 3B

⇒ 396 + B + 99 = 12B

⇒ 396 + 99 = 12B

⇒ 495 = 12B

⇒ B = 45.

Substitute B = 45 in (v), we get

⇒ (B + 99)/4 = C

⇒ (45 + 99)/4 = C

⇒ C = 36

Now,

B + C = 45 + 36

         = 81.

Therefore, Sum of the other two shares = 81

Hope this helps!