Question

32. A charge q is located at the centre of a cube. The
electric flux through any face of the cube is
2πα
(1) 6(4πεο)
(2)
4πα
6(4πεο)
πα
(3) 6(4πεο)
(4
q
6(4πεο)
pls don't spam​

Answer 1

Answer:

add me as the brainliest then I will asnwer

Explanation:

have a great day

Answer 2

Electric flux:

It is the measure of electric field intensity passing through the given area.

☆According to gauss's law electic flux through closed surface enclosing a charge:

$\boxed{\bf \phi = \dfrac{q_{in}}{\epsilon_0}}$

Since the charge is placed in the cube, so

$\implies \rm \phi_{cube} = \dfrac{q_{in}}{\epsilon_0}$

Now, cube has 6 faces, so flux from each face will be:

$\implies \rm \phi_{each\: face} = \dfrac{q_{in}}{6 \epsilon_0}$

》Expression correctly satisfying above form;

$\boxed{\rm \phi = \dfrac{4\pi q}{6(4\pi \epsilon_0)}}$