32 A compound has the following % composition-Zn=22.65%,5=11.15%;0=61.32%
and H=4.88%
It's relative molecular mass is 287 g. Calculate it's molecular formulae assuming that
all the hydrogen in the compound is present in combination with oxygen as water of
crystallisation
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Explanation:
A compound has the following % composition. Zn=22.65 %; S=11.15 %; O=61.32 % and H=4.88%. Its relative molecular mass is 287 g. Its molecular formula assuming that all the hydrogen in the compound is present in combination with oxygen as water of crystallization is:
[Zn=65, S=32, O=16, H=1]
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