32 a cube + 108 b cube( factorise)
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Answer:
32a³+108b³ = 4 ( 8a³ + 27b³) = 4[(2a)³+(3b)³] = 4(2a + 3b)(4a²-6ab+9b²)
Step-by-step explanation: The fact is that a³+b³ = (a+b)(a²-ab+b²)
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