Question

32. A father is twice as old as his son, 20 years
ago, the age of the father was 12 times the
age of son. The present age of the father in
years) is:
(A) 44
(B) 32
(C) 22
(D) None of these​

Answer 1

Answer:

Given,

The Father is Twice as old as his son .

20 years ago , the age of the father was 12 times the age of the son.

To Find,

The Present Age

Solution,

⇒Suppose the Present age of the son be x

And, Suppose the Present age of the Father be y

According to the First Condition :-

The Father is Twice as old as his son .

⟹ y=2x

According to the Second Condition :-

20 years ago , the age of the father was 12 times the age of the son.

⟹(y−20)=12(x−20)

⟹y−20=12x−240

⟹2x−20=12x−240

⟹2x−12x=−240+20

⟹−10x=−220

⟹10x=220

⟹x= 10/220

⟹ x=22 years

Now Put the value of x in First Condition :-

⟹y=2x

⟹y=2×22

⟹ y=44 years

Therefore,

Age of the Father=y=44 years