Question

32. An organic compound ‘A’ with molecular formula C4H8O2 was hydrolysed with dil. H2SO4
to give a carboxylic acid ‘B’ and an alcohol ‘C’. ‘C’ on dehydration gives ethene and ‘C’ also on
oxidation gives back ‘B’. Identify ‘A’, ‘B’ and ‘C’ and write the chemical equations for the
reactions involved

Answer 1

Answer:

Explanation:

here

C + dehydration ------> CH₂=CH₂

and C is alcohol then

C must be CH₃-CH₂-OH

If C is oxidized give B

CH₃-CH₂-OH + Oxidation ----> CH₃-COOH

B is CH₃-COOH

A + dil. H₂SO₄ ------->  CH₃-COOH + CH₃-CH₂-OH

Then A is CH₃-CH₂-CO-O-CH₃(Methyl propionate)

Reaction involved

CH₃-CH₂-CO-O-CH₃+ dil. H₂SO₄ ------->  CH₃-COOH (B) + CH₃-CH₂-OH(C)

CH₃-CH₂-OH (C)------> CH₂=CH₂ +H₂O

CH₃-CH₂-OH (C)  + O₂------>  CH₃-COOH (B)