Question

32. Calculate the quantity of Na,Co, which has same
number of atoms as the number of protons present in
10 g Caco,
(A) 20 g
(B) 88.33 g
(C) 44 g
(D) 60 g
give explanation
​

Answer 1

Answer:

So, 100g of CaCO

3

contains 6×10

23

molecules.

But, We are looking for 10g.

So in 100g $$6 \times 10^{23} So in

10g 6×10

22

molecules.We know that,

The number of protons in a molecule is directly its atomic number.

We know that,

The number of protons in a molecule is directly its atomic number.

So, $Ca= 18

C = 6

O = 8×3 = 24

Totally, 50 protons and 50 electrons in one molecule of CaCO

3

And now,

Number of protons in 10g

= Number of protons in 6×10

22

molecules.

= 50×6×10

22

= 3×10

24

protons.