Question

32. Construct a rhombus ABCD with AC = 6cm & BD = 4cm​

Answer 1

Given :  AC=6 cm

BD=4 cm

To Find : construct the Rhombus ABCD

Solution:

Diagonal of Rhombus bisect each other.

Step  1: Draw  a line segment AC = 6  cm

Step 2 : Using compass width more than 3 cm , and taking A as center , draw arcs on both sides of AC

Step 3 : Keeping compass width same and  taking A as center , draw arcs on both sides of AC such that it intersect arcs drawn in previous step at X and Y

Step 4 : Join X and Y , intersecting AC at O

Step 5 : Using compass width = 2 cm  (BD/2 = 4/2 = 2)  and taking O as center  cut XY at  B and D

Step 6 : Join AB , BC , CD and AD

Rhombus ABCD is constructed

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Answer 2

Step-by-step explanation:

Step 1: Draw a line segment AC = 6 cm

Step 2: Using compass width more than 3 cm, and taking A as center, draw arcs on both sides of AC

Step 3: Keeping compass width same and taking A as center, draw arcs on both sides of AC such that it intersect arcs drawn in previous step at X and Y

Step 4: Join X and Y, intersecting AC at O

Step 5: Using compass width = 2 cm (BD/2 = 4/2 = 2) and taking O as center cut XY at B and D

Step 6: Join AB, BC, CD and AD

Rhombus ABCD is constructed.