Question

32. Find the area of the triangle two sides of which 8cm and 10 cm the perimeter is 42 am​

Answer 1

Area of triangle = /s(s a)(s - b)(s - c) Here, s is the semi-perimeter,and a, b, care the sides of the triangleaGiven a = 18 cm, b 10 cmand Perimeter = 42 cmPerimeterSemi-Perimeter =S-

2S =-2S 21 cm

Step-by-step explanation:

Now,Perimeter = 42cma+b+C = 42 cm18 cm + 10 cm +C= 42 cm28 cm +C = 42 cmma 18 cmC 42-28 cmC 14 cmArea of triangle = ys(s - a)(s-b)(s - c)Putting a = 18 cm, b=10 cm, c= 14 cm &s = 21 cmArea of triangle =21(21 - 18)(21 - 10)(21 - 14)=21(3)(11)(7)21 (7 X 3)(11)=/21 (21)(11