32. Frequency distribution is given in following table : (x) Variable Frequency 5 7 12 6 16 8 20 4 23 5 What is the arithmetic mean? 43 34 71 (A) دا دیا (B) 17 5 5 (C) C | دا ) (D) 5 5 .
Answers
Given,
Variable Frequency 5 7 12 6 16 8 20 4 23 5
To find,
arithmetic mean
Solution,
Mean = sum of the numbers/number of numbers
= 106/10
= 10.6
Thus, the mean of the given frequencies id 10.6
- The Arithmetic Mean of given frequency distribution is equal to 14.33.
Given :-
- Variable (x) = 5, 12, 16, 20, 23 .
- Frequency (F) = 7, 6, 8, 4, 5 .
To Find :-
- Arithmetic Mean = ?
Formula used :-
- Arithmetic Mean = ⅀Fi•Xi / ⅀Fi .
Solution :-
Arranging the data in the Frequency distribution table we get :-
Variable(Xi) ------ Frequency(Fi) ------ Fi•Xi
5 ------------------------- 7 ------------------ 35
12 ------------------------ 6 ------------------ 72
16 ------------------------ 8 ----------------- 128
20 ----------------------- 4 ------------------ 80
23 ----------------------- 5------------------- 115
Total ------------ ⅀Fi = 30 -----⅀Fi•Xi = 430
So,
→ Arithmetic Mean = ⅀Fi•Xi / ⅀Fi
→ Arithmetic Mean = 430/30
→ Arithmetic Mean = 43/3
→ Arithmetic Mean ≈ 14.33 (Ans.)
Hence, the required arithmetic mean is equal to 14.33 .
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