Question

32 g of a gas SOx occupies 11.2 L at STP. The value of 10x is:​

Answer 1

Answer:

32 grams of a gas SOx occupies 11.2 L at STP. One mole of a gas SOx occupies 22.4 L at STP. So 11.2/22.4 moles of SOx weighs 32 grams => 0.5 moles of SOx weighs 33 grams hence 1 mole of SOx weighs 64 grams => (32+16x)=64 =>16x=32 =>x=2. So the value of 10x is 20. Hope it helps you.

Explanation:

Answer 2

The value of 10x is 20.

Given:

32 g of a gas SOx occupies 11.2 L at STP.

To Find:

The value of 10x.

Solution:

To find the value of 10x we will follow the following steps:

As we know,

$Number \: of \: moles = \frac{given \: mass}{molecular \: mass}$

The molecular mass of SOx = 32 + 16x

(molecular mass of sulphur is 32 and molecular mass of oxygen is 16).

Now,

The number of moles can be calculated as,

$number \: of \: moles \: = \frac{given \: volume \: in \: litre}{22.4}$

So, equating both the equations we get,

$\frac{given \: mass}{molecular \: mass} = \frac{given \: volume \: in \: litre}{22.4}$

$\frac{32}{32 + 16x} = \frac{11.2}{22.4}$

$\frac{32}{32 + 16x} = \frac{1}{2}$

$32 \times 2 = 1 \times (32 + 16x)$

$64 = 32 \: + 16x$

$64-32 = 16x$

$\frac{32}{16} = x$

$x = 2$

So,

10x = 10×2 = 20

Hence, the value of 10x is 20.

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