Question

32 g of methane (molar mass 16 g/mol) is mixed with 192 g of oxygen (molar mass 32 g/mol). Presuming that these gases donot react with each other, what is the mole fraction of methane ?​

A) 0.25
B) 6
C) 0.167
D) 4

Answer 1

Answer:

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Answer 2

Given - Mass of methane and oxygen

Find - Mole fraction of methane

Solution - Mole fraction of methane is A) 0.25.

The mole fraction of methane can be calculated as - Mole fraction = moles of methane/total number of moles of solution

Number of moles = mass/molar mass

Moles of methane = 32/16

Moles of methane = 2

Moles of oxygen = 192/32

Moles of oxygen = 6

Keep the values in the formula to find the value of the mole fraction of methane.

Mole fraction of methane = 2/(2+6)

Mole fraction of methane = 2/8

Mole fraction of methane = 0.25.

Thus, the mole fraction of methane is A) 0.25.